Mathematics
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OpenStudy (anonymous):
(x^3-8) is factored to
(x-2)(x^2+2x=2) can someone explain this, or give me the formula to do a similar problem
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OpenStudy (rsadhvika):
google a^3-b^3 formula
OpenStudy (anonymous):
why the b^3, the problem only has one exponent
OpenStudy (rsadhvika):
observe that 8 = 2^3
OpenStudy (anonymous):
\[a^3-b^3 = (a-b)(a^2+ab+b^2)\]
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OpenStudy (rsadhvika):
x^3-8 = x^3-2^3
OpenStudy (anonymous):
this x^3-8 = x^3-2^3 is the same as (x-2)(x^2+2x=2
OpenStudy (anonymous):
correct
OpenStudy (primeralph):
@Hero Let's try to arrive at the solution purely.
Seems intricate.
OpenStudy (rsadhvika):
It is easy to see right, just 6 terms out of which 4 cancel out when you expand.
you looking for derivation of formula ?
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OpenStudy (anonymous):
@rsadhvika
OpenStudy (rsadhvika):
yeah ?
OpenStudy (primeralph):
Can someone post this as a new question? How to prove it.
OpenStudy (rsadhvika):
x^n-y^n = ... that proof you want ?
OpenStudy (primeralph):
Yes. For this case where n = 3.
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OpenStudy (primeralph):
I'm working on it, but I'd like to see what others have.
OpenStudy (rsadhvika):
im doing the same right now, trying to understand the proof
OpenStudy (primeralph):
@Hero Got it.
OpenStudy (primeralph):
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