Mathematics
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OpenStudy (anonymous):
need help simplifying
X+7 6
------ + ------
2x+12 x^2-36
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OpenStudy (anonymous):
so far ive got
x+7 6
---- + ----
2(x+6) (x+6)(x-6)
OpenStudy (kkutie7):
try finding a common denominator to start.
HanAkoSolo (jamierox4ev3r):
you could also try cross multiplying because it looks like a proportion
OpenStudy (anonymous):
i need the denominators to be the same
OpenStudy (luigi0210):
@tyler123456789 try using @Kkutie7 's way
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OpenStudy (anonymous):
how do i find the common denominator
OpenStudy (luigi0210):
Factor
OpenStudy (anonymous):
so.... multiply x-6 to both numerator and denominator on the left side and 2 on the left?
OpenStudy (luigi0210):
Yup, show me what you get
OpenStudy (jdoe0001):
let's take a peek at the denominators
2x+12
can you get a common factor off that?
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OpenStudy (jdoe0001):
just that one expression
OpenStudy (luigi0210):
@jdoe0001 he already factored them
OpenStudy (jdoe0001):
ohh, ok,
what about \(\bf x^2-36\)
keep in mind that \(\bf (a-b)(a+b) = (a^2-b^2)\)
OpenStudy (luigi0210):
@jdoe0001 all under his question
OpenStudy (anonymous):
im confused
so when i multiply both i get
x+7(x-6) 6(2)
--------- + --------
2(x+6)(x-6) 2(x+6)(x-6)
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OpenStudy (jdoe0001):
\(\bf \cfrac{x+7}{2x+12}+\cfrac{6}{x^2-36}\\
\cfrac{x+7}{2(x+6)}+\cfrac{6}{(x+6)(x-6)}\)
OpenStudy (jdoe0001):
the LCD will be really the 2nd denominator
OpenStudy (luigi0210):
Good now multiply the top and continue with the needed operation
OpenStudy (jdoe0001):
\(\bf \cfrac{x+7}{2(x+6)}+\cfrac{6}{(x+6)(x-6)} \implies \cfrac{\square?+\square?}{(x+6)(x-6)}\)
OpenStudy (anonymous):
x^2 + x - 30
------------
2(x+6)(x-6)
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OpenStudy (jdoe0001):
maybe I needed the 2 as well :/
OpenStudy (luigi0210):
@tyler123456789 there you, that's it
OpenStudy (luigi0210):
Now factor that.
OpenStudy (anonymous):
i dont understand, how?
OpenStudy (anonymous):
nothing sums to 1 and multiplies to 30
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OpenStudy (anonymous):
oh wait
(x+6)(x-5)
---------
2(x+6)(x-6)
OpenStudy (luigi0210):
\[\frac{(x+6)(x-5)}{2(x+6)(x+6)}\]
OpenStudy (luigi0210):
*(x-6)
And correct, now cancel common factors
OpenStudy (anonymous):
si i get x-5
-----
2x-12
OpenStudy (luigi0210):
Yup!
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OpenStudy (anonymous):
thank you so much
OpenStudy (luigi0210):
No problem :)
OpenStudy (anonymous):
new fan