Question

Log Question. College Algebra

Answer 1

logbase5(2x+4)=2

Answer 2

\[\log_{5} (2x+4)=2\]

Answer 3

becomes 2x+4=25, I dont see what we take the base and raise it to the two

Answer 4

well you got that right, you exponentiate both sides by 5 to cancel out the log base of 5 now just solve for x by subtractig 4 and dividing by 2

Answer 5

Because...

if\[\Large \log_a b = x\]then\[\Large a^x = b\]

Answer 6

^ correct

Answer 7

\[5^{2}=2x+4\]

Answer 8

25=2x+4

Answer 9

That's what a log is for - what power do you need to raise the base, to get the number inside the log.

Answer 10

21=2x

Answer 11

x=21/2

Answer 12

that's what you are going to get

Answer 13

Ok, so the question is just a complicated log that we are suppose to find out?

Answer 14

well if you are solving for x then yes x=21/2 because if you plug that back in you get

\[\log_5(2(\frac{ 21 }{ 2 }+4)=2\]
\[\log_5(21+4)=\]
\[\log_5(25)\]
\[\log_5(5^2)=2\]
\[2=2\]

That means x=21/2 is true