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OpenStudy (anonymous):
HELP!!!! How much heat is absorbed during production of 112g of NO by the combination of nitrogen and oxygen? N2(g)+O2(g)→2NO(g), ΔH = + 43 kcal/mol
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OpenStudy (festinger):
Find the amount of mols of NO in this reaction, then multiply it by 43kcal.
OpenStudy (anonymous):
112g of NO x 1 Mole NO/Molar mass of NO (cancels out grams) x 43Kcal/ 1 Mol NO = answer! for these, you want to convert to moles first since kcal is over moles.
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