Question

z

Answer 1

okay

Answer 2

so first of all, you want to fine the reference angle.

Answer 3

see 11 is larger than 6 right?

Answer 4

so you do this : 11/6 - 6/6 = -5/6 pi (sorry I didn't write the negative and pi in the equation)

Answer 5

5/6 pi is equal to 150

Answer 6

its -11/6

Answer 7

but since it's negative,

Answer 8

it's gonna be 210

Answer 9

cuz it's gonna go clockwise do you get this part?

Answer 10

how did you get -5/6 and why did you subtract one?

Answer 11

and wehre is the 210 and 150 come from

Answer 12

okay

Answer 13

simpler way

Answer 14

@musiklover317 I have another question for you

Answer 15

look. you know that you want to fine the reference angle to solve for sin csc cot etc.

Answer 16

@Hero dude. I don't have time to deal with you. Don't bother me. I have my own hw to do but it's delay because of you.

Answer 17

just deal with it by yourself.

Answer 18

Answer that last question and then I'll be finished with you.

Answer 19

ha. look. I don't want to waste my time, so why don't you argue with another person.

Answer 20

@jhalt sorry about that. so 180 degrees = pi

Answer 21

Suppose the angle is 216 degrees and the area of a sector is 15pi. What's the radius of the circle?

Answer 22

There bro. I even posted it here for you

Answer 23

huh I am confused. Where did you get the 216 egrees

Answer 24

in order to find the the reference angle, you have to subtract the angle given (larger than 180) to 180

Answer 25

so 6pi/6 is pi

Answer 26

okay

Answer 27

That was @musiklover317 math question

Answer 28

so you have to subtract 11pi/6 by 6pi/6

Answer 29

ok

Answer 30

then you'll get -5pi/6

Answer 31

5pi/6 is 150 right?

Answer 32

thast what I am confused about

Answer 33

oh do you have the unit circle with you?

Answer 34

ya

Answer 35

then you know that 5pi/6 is 150

Answer 36

5pi/6 is in radian form and 150 is in degree form

Answer 37

yes I understand. I see 150 on the circlue. BUt I apologize but why did you subtract 180?

Answer 38

because the angle was larger than 180 (or pi)

Answer 39

yes but why thought?

Answer 40

oh your trying to make it less?

Answer 41

why not just say -30 degrees instead?

Answer 42

because 11pi/6 - pi/6 is not gonna work, you see?

Answer 43

but that's the next step though

Answer 44

150's reference angle is 30 which is pi/6

Answer 45

and it's (rad(3)/2,1/2) [(cos,sin)]

Answer 46

and you know how to find the rest of them.

Answer 47

hey I really have to go now good luck!

Answer 48

Talk about taking some obscure long way of solving

Answer 49

can you ehlp me hero?

Answer 50

I'll post the solution for the first one. You're on your own with the rest

Answer 51

\[\theta = -\frac{11 \pi}{6}\]

Answer 52

your wrong

Answer 53

sin is y/r and cos is x/r

Answer 54

Okay, so you have all the formulas in front of you so you don't need that

Answer 55

Anyway, you need to find \(\sec \theta\)

Answer 56

ok

Answer 57

\[\sec(\theta) = \frac{r}{x}\]

Answer 58

Now insert theta:

\[\sec\left(-\frac{11 \pi}{6}\right) = \frac{r}{x}\]

Answer 59

substitute \(\pi = 180\)

Answer 60

\[\sec\left(-\frac{11(180)}{6}\right) = \frac{r}{x}\]
\[\sec\left(-11(30)\right) = \frac{r}{x}\]
\[\sec\left(-330 \right) = \frac{r}{x}\]

Answer 61

\[\sec\left(-330 \right) = \frac{r}{x}\]

\[\sec(\theta)= \frac{1}{\cos(\theta)}\]

Answer 62

So:

\[\sec(-330)= \frac{1}{\cos(-330)} \]

Answer 63

But -330 degrees is just 30 degrees on the circle, so:

\[\sec(-330)= \frac{1}{\cos(30)}\]

Answer 64

Solve the rest

Answer 65

You should be familiar with the unit circle