A plane takes off at an angle of elevation of 15° and travels in a straight line for 3,000 meters. What is the height of the plane above the ground at this instant?

Question

anonymous · Answer

Use the definition of velocity and some trigonometry

anonymous · Answer

Yea, Thats where the problem is. It's online course so It's not really in depth so I havent learned all of that. Thats why I came here for help on the question

anonymous · Answer

yes, id help you, but i am pretty lazy

anonymous · Answer

um, thanks for trying i guess? Have a good day

anonymous · Answer

i didn't try, and its night time here

anonymous · Answer

Sarcasm. And that's good for you I'm just ending the conversation goodbye

rane · Answer

do u know how the diagram would look like, if yes can u pls draw it for me

anonymous · Answer

Oh thank you for helping! I'm sorry the question only has the passage.

rane · Answer

ok bt i got the ans if u want

anonymous · Answer

Yes please!

rane · Answer

|dw:1374565957786:dw|

rane · Answer

so...
  

    3000sin15
  = 776.46m

anonymous · Answer

Okay thank you two! :) You guys are life savers

rane · Answer

anytime :)

anonymous · Answer

okay so you know if you drew the diagram, you would end up with a 'right angled triangle' to solve - so to speak
|dw:1374566543034:dw|

So using this diagram, you have the length of the hypotenuse, and you want to find the height, which is the 'opposite length to the angle'

So using SOHCAHTOA
we have 
$$\sin 15 = \frac{ height }{ 3000 }$$

height=3000 sin 15

I think this is correct anyway, it is how I would interpret it

anonymous · Answer

K thanks alot! :)