Question

2x^2 - 4x + 1 = 0

Answer 1

What do you need to find?

Answer 2

im doing Quadratic Equations but i have to solve for x

Answer 3

x=\[-b \pm \sqrt{b^2-4(a*c)}/2a\]

Answer 4

Alright, well you can either factor it or use the quadratic equation. For this one, I would use the quadratic.
So you would get plug in the values. The solution(s) you would get once you solved would be your x value(s).

Answer 5

\[x=(4\pm \sqrt{16-4(2*1)})\]

Answer 6

there is a /2 in that eqn..sorry

Answer 7

okay so would I put the equation on the other side of the zero

Answer 8

Ignore the zero for now.

Answer 9

ok

Answer 10

so i did (2x+1) (x ) but im stuck

Answer 11

You'll need to do that quadratic equation for this since it does not factor nicely.

Answer 12

I am not sure how to do that

Answer 13

@Krishnadas gave you the equation earlier

Answer 14

ohh ooops

Answer 15

so the equation they gave me i divide it

Answer 16

im still stuck im not sure what i am doing

Answer 17

What part are you stuck on?

Answer 18

im doing the equation that @Krishnadas did but im not sure if i divide it all cause im doing this without a calcutator so its a little harder for me