A simple random sample of voters is taken from the voters in a large state. Using the methods of our course, researchers construct an approximate 99% confidence interval for the percent of the state’s voters who will vote for Candidate A. The interval goes from 37.3% to 48.7%. In the sample, the percent of voters who will vote for Candidate A is equal to ____________%.
well, since an interval is centered around the sample mean .... what is the midpoint between 37.3 and 48.7?
even if they are using "approximation" ; that is still 3 standard deviations centered about the sample mean
The middle point is (37.3+48.7)/2 =43
For A, I would find the center of 37.3% to 48.7%. i.e. (37.3 + 48.7)/2 = 43.0 the interval from 43 to 48.7 = 5.7 represents 2.58 σ so 5.7/2.58 = 2.21 % per σ
is correct the statement?
\[p\pm E\] \[37.3~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~48.7\\~~~|<------p------>|\\~~~~~~~~~~~~~-E~~~~~~~~~~~~~~~~~~~~+E\] the sample percentage is the midpoint between the extremes
add the ends and divide in half \[\frac{37.3+48.7}{2}=\frac{86.0}{2}=43\]
43% of the sample choose A
finding the sample size would be fun :)
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