A person purchases a television set for Rs 16000. It's estimated life is 20 years. If yearly depreciation is assumed to be constant. Find the rate of depreciation and price after 8 years.
the depreciation is constant sooo; 16000/20
since 8 years of depreciation have accumulated .... the price is 16000 - 8(dep)
t8= 16000+(8-1)(-800) = 16000-5600 = 10400
but answer given is 9600
why would you only do it for 7 years?
isn't this an arithmetic sequence with first term 16000 and common difference - 800 ?? so the formula of t8 would be t8 = a+(n-1)d ?
if you insist on starting at t1, then t(1+8) = t9
if you start at t0, then there is no need to subtract 1
t0 = 16000 - 800(0) t1 = 16000 - 800(1) t2 = 16000 - 800(2) ... t8 = 16000 - 800(8)
:) got u ... thanks !!
youre welcome
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