Question

Simplify. 3 times the 3rd root of 16

5 times the 3rd root of 2

3 times the 3rd root of 2

12 times the 3rd root of 2

27 times the 3rd root of 2

Question 3 (Multiple Choice Worth 2 points)

The girls group rented 2 canoes and 3 inner tubes for a total cost of $80. The boys group rented 1 canoe and 7 inner tubes for a total cost of $95. What is the cost to rent 1 canoe?

$10

$15

$25

$18

Question 4 (Multiple Choice Worth 2 points)

Simplify 125 to the power of negative 2 over 3

–25

25

one over 25

negative one over 25

Answer 1

you should really try to do homework on your own

Answer 2

whats you guesses ?

Answer 3

1) b
2)c
3)a
4)a

Answer 4

i think 4s wrong tho

Answer 5

i think there is a mistake in question 4

Answer 6

are the other 3 correct?

Answer 7

-1/25

Answer 8

\[\frac{125^{-2}}{3} = \frac{1}{125^2*3}\]

Answer 9

then what? lol

Answer 10

i think there is a mistake in the actual answer choices because it makes no since when you have a big number to the neg power your gonna get a small number..

Answer 11

oh :/ these are the options -25 25 1/25 -1/25

Answer 12

mathstudent will help because im confused on Q4

Answer 13

Is the question in 4.

\( \large {125^{ -\frac{2}{3} } }\) ?

Answer 14

were my other three correct?

Answer 15

yes :) thats the question

Answer 16

oh :o

Answer 17

\(\large {125^{ -\frac{2}{3} } }\)

\( = \large \dfrac{1}{125^{ \frac{2}{3}} } \)

\(= \large \dfrac{1}{ (\sqrt[3]{125})^{2} } \)

\(= \large \dfrac{1}{ 5^{2} } \)

\(= \large \dfrac{1}{ 25 } \)

Answer 18

u mean c?

Answer 19

Correct. For 4, the answer is C.

Answer 20

Are you sure your answer choices for 1 are correct? I don't see the correct answer in any of the 4 choices.

Answer 21

b is 6 ^3sqrt2

Answer 22

This is problem 1, right?

\( \large{3 \sqrt[3]{16} }\)

Answer 23

yes

Answer 24

its 6 ^3sqrt2 correct?

Answer 25

Choice B above reads "3 times the 3rd root of 2"

Answer 26

i know, thats wrong its supposed to be 6\[6 ^3\sqrt{2}\]

Answer 27

\( \large{3 \sqrt[3]{16} } \)

\(= \large{3 \sqrt[3]{8 \times 2} } \)

\(= \large{3 \sqrt[3]{2^3 \times 2} } \)

\(= \large{3 \times 2 \sqrt[3]{2} } \)

\(= \large{6 \sqrt[3]{2} } \)

Then it's correct. Problem 1: Answer is B: \(\large{6 \sqrt[3]{2} } \)

Answer 28

yay

Answer 29

Why did you write 4 answers above when there are only 3 questions?

Answer 30

Which expression represents 8 x to the three sevenths power in radical form?

8 times the 3rd root of x to the seventh
8 times the seventh root of x to the third power
the seventh root of 8 x to the third power
the third root of 8 x to the seventh power I GOT A

What is the equation of the line that passes through the point (4, 1) and is perpendicular to the line y = –2x + 4?

y = negative one half x – 3
y = negative one half x + 1
y = one half x + 4
y = one half x – 1 EITHER A OR B

Solve 6the square root of x plus one) – 3 = 15

x = 8
x = 71
x = 75
x = 107 I GOT B

Which system of inequalities is graphed below?

Answer 31

The canoe question is $25 per canoe renatal.

Answer 32

it was an accident

Answer 33

thats what i got :)

Answer 34

This?
\( \large{8x^\frac{3}{7} } \)

Answer 35

Is the 8 also raised to teh poer?

Answer 36

its 8x 3/7

Answer 37

Or this?

\(\large{(8x)^\frac{3}{7} }\)

Answer 38

8x^3/7

Answer 39

If there are no parentheses, then only x is raised to the power; the 8 is not raised to the power.

Answer 40

ya, no parenthesis

Answer 41

\( \large{8x^\frac{3}{7} }\)

\(\large{ = 8 \sqrt[7]{x^{3}} } \)

When you have a fraction as a power, the numerator is an exponent and the denominator is the index of the root.

Answer 42

ohh ok

Answer 43

Answer is B.

Answer 44

is the next question either a or b?

Answer 45

What is the equation of the line that passes through the point (4, 1) and is perpendicular to the line y = –2x + 4

The slope of the given line is -2. That means the slope of the perpendicular line is 1/2.
That eliminates A and B.

Answer 46

oh i got -1/2 slope

Answer 47

okk so c or d :3

Answer 48

What are the slopes of perpendicular lines?

Answer 49

umm?

Answer 50

If you are given the slope of a line, what do you know about the slope of its perpendicular?

Answer 51

is it half?

Answer 52

No. The slopes of two perpendicular lines multiply to -1.
The slopes of perpendicular lines are negative reciprocals.
That means that if you know the slope of a line, to get the slope of its perpendicular,
1. write the slope of the line as a fraction, then
2. flip the fraction, then
3. change the sign.

Answer 53

The given line is
y = -2x + 4
What is the slope of this line?

Answer 54

-2

Answer 55

A line written in the slope-intercept form has the equation
\( y = mx + b \)
where
m = slope and
b = y-intercept

Answer 56

ok :) -2 = slope

Answer 57

Correct. m is the number that multiplies x in the equation of a line, and m is the slope, so in your problem, the slope is -2.

Answer 58

Now to find the slope of the perpendicular, follow my 3 steps above.
1. write the slope as a fraction.

Answer 59

-2/1

Answer 60

Good.
2. flip the fraction

Answer 61

1/-2

Answer 62

Good.
3. change the sign.

Answer 63

1/2

Answer 64

Good. The slope we need is 1/2.
We know the equation of a line is
y = mx + b, where m = slope. Our slope is 1/2, so we can put 1/2 in form:

\( y = \dfrac{1}{2}x + b \)

Answer 65

y=4?

Answer 66

i mean b=4

Answer 67

Not necessarily.
This is how we find b.

We are given a point \( (x, y) = (4, 1) \)
We input that point into x and y of the eqation and solve for b.

\( 1 = \dfrac{1}{2}(4) + b \)

\(1 = 2 + b\)

\(-1 = b \)

\(b = -1\)

Now that we have b = -1, we can complete our equation:

\( y = \dfrac{1}{2}x - 1 \)

That is the equation we need. As you can see it's D.

Answer 68

ohh ok :)

Answer 69

btw i got a for the next one not b

Answer 70

First I need to understand what this means.
Solve 6the square root of x plus one) – 3 = 15

Answer 71

\( \large{ 6 \sqrt{x + 1} - 3 = 15 } \)
Is this the correct equation?

Answer 72

6 sqrt x+1-3=15

Answer 73

yes :)

Answer 74

First, add 3 to both sides of the equation.

Answer 75

k

Answer 76

is 8 right?

Answer 77

\(\large{ 6 \sqrt{x + 1} - 3 = 15 } \)

\(\large{ 6 \sqrt{x + 1} = 18 } \)

Answer 78

Now divide both sides by 6, to get rid of the 6 multiplying the square root.

Answer 79

ok

Answer 80

\(\large{ \sqrt{x + 1} = 3 } \)

Answer 81

Now you need to square both sides to get rid of the square root.

Answer 82

\(\large{ (\sqrt{x + 1})^2 = (3)^2 } \)

\(\large{ x + 1 = 9 } \)

Subtract 1 from both sides:

\(\large{ x = 8 } \)

Answer 83

so i was right :D

Answer 84

Now make sure 8 works in the original equation:
\(\large{ 6 \sqrt{8 + 1} - 3 = 15 } \)

\(\large{ 6 \sqrt{9} - 3 = 15 } \)

\(\large{ 6 \times 3 - 3 = 15 } \)

\(\large{ 18 - 3 = 15 } \)

\(\large{ 15 = 15 } \)

x = 8 is correct

Answer 85

yay

Answer 86

Answer is A

Answer 87

ok, what about the next one?

Answer 88

The last problem, you need to look at the graph. There are two inequalities graphed.

Answer 89

is it b or c?

Answer 90

i take that back

Answer 91

4x-y is less than or equal to -10 ?

Answer 92

One is a dashed line shaded blue under it.
Form the y-intercept and slope its inequality is:
\( y < \dfrac{1}{ 2}x +4 \)

The other inequality has a solid line and is shaded orange underneath.
From the y-intercept and slope the inequality is:
y≤4x+10

Those are the two inequalities.

Answer 93

c?

Answer 94

y <= 4x + 10
-4x + y <= 10
4x - y >= -10

Answer 95

You didn't show the choices with that question.

Answer 96

2x – 5y greater than or equal to –20
4x – y > –10

2x – 5y > –20
4x – y greater than or equal to –10

2x – 5y < –20
4x – y less than or equal to –10

2x – 5y less than or equal to –20
4x – y < –10

Answer 97

a?