x + 2y = 5 x - 3y = 7 What is the value of the y-determinant?
cramer's rule, right?
I believe so.
so replace the y column on the coefficient matrix for x and y by the answer column...
\[Ax+Cy=M\]\[Bx+Dy=N\]|dw:1374600449433:dw|
the y matrix is found by replacing the answer column into the y column|dw:1374600632825:dw|
you get this|dw:1374600697057:dw|which you take the determinant of
$$ \begin{matrix} x & y\\ \hline\\ 1 & 2 &|& \color{red}{5}\\ 5 & -3 & | &\color{red}{7}\\ \end{matrix} \\D_y = \left\lbrack \begin{matrix}\\ 1 & \color{red}{5}\\ 5 & \color{red}{7}\\ \end{matrix} \right\rbrack $$
you still have to take the determinant of that though I believe.
yes
S.Marie23 so, what would be the determinant of \(D_y\) matrix?
hmm, actually my matrix has a typo :(
$$ \begin{matrix} x & y\\ \hline\\ 1 & 2 &|& \color{red}{5}\\ 1 & -3 & | &\color{red}{7}\\ \end{matrix}\\ \\ \begin{matrix}\\ 1 & \color{red}{5}\\ 1 & \color{red}{7}\\ \end{matrix} $$
jdoe would it be 2 or -2?
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