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Mathematics 22 Online
OpenStudy (nptweezy):

Somebody Plz ASAP (Medal +Fan) Pic Included

OpenStudy (nptweezy):

I don't know at all

OpenStudy (nptweezy):

@jdoe0001

OpenStudy (anonymous):

You have a y-int of 1 and a slope of 1. Change each equation into y=mx+b m=slope b=y-intercept

OpenStudy (nptweezy):

that suck me even more I suck at math @AlwaystheBookworm

OpenStudy (nptweezy):

the first suck was suppose to be made

OpenStudy (anonymous):

Okay. Let's go through this step by step. First, look at the graph. You'll see that the line crosses the y-axis at 1. That is your y-intercept. Now look at where the line crosses the x-axis at -1. Looking at the two intercepts, you can see that it has a slope of 1. The slope is rise/run. Now you know the equation is y=x+1. Look at your answer choices. Take each one and convert it into the form of y=mx+b.

OpenStudy (anonymous):

It you look at the first one, you have x-y=-1. Bring the x to the other side. -y=-x-1 You can not have a -y, so divide everything by -1. y=x+1

OpenStudy (queelius):

If AlwaystheBookworm's approach (which I prefer) is not intuitive for you, you can always resort to the following formulas: If we have two points on the line, (x1, y1) and (x2, y2), then we can determine the slope, m: m = (change in y) / (change in x) = (y2 - y1) / (x2 - x1) If we have the slope and we have a point (x1, y1) on the line, then a formula for the line is: y - y1 = m * (x - x1) Looking at the graph, one point is (0, 0) and another point is (1, 1).

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