Question

help please work attached

Answer 1

@nickirivera

Answer 2

@satellite73

Answer 3

i did some research and found it was about 45 meters

Answer 4

can u tell me how u got that answer

Answer 5

http://www.pmel.noaa.gov/vents/nemo1998/education/pressure.html

pressure increases by 14.6 for every 10 meters in depth

Answer 6

ok but i got the answer wrong

Answer 7

well what units are they looking for?

Answer 8

i posted everything on here thats y i did a screen shot

Answer 9

@jazzyfa30 From what I remember, there's some information above the screen that you showed in another question you posted. It might be important to this question.

Answer 10

ok hold on ill screen shoot it for you

Answer 11

did that help

Answer 12

try 10* (65-14.6)/14.6 = 34.5 meters
or convert to feet
113.2 ft

Answer 13

wow you had the relationship right there the whole time lol

p = 0.43d

--> 65 = .43d
--> d = 151.16

Answer 14

nope @johnweldon1993 help please

Answer 15

Right....remember that lsat question where we found the equation for this??

P = .43d

?

Well now...we have a P value ...and we want to solve for 'd' so

\[\large 65 = 0.43d\]

and solve for 'd'

Answer 16

umm subtract

Answer 17

Nope...remember you want to isolate 'd'...you don't want .43d...you want d...so you would divide both sides by .43 right?

Answer 18

ohhh ok

Answer 19

And you get that D = ???

Answer 20

d = 151.16

Answer 21

That would be correct :)

Answer 22

but its saying thats wrong

Answer 23

Round to the nearest whole number...

Answer 24

oh my goodness...instructions say round

Answer 25

ohhh so its 152

Answer 26

no 151

Answer 27

does 151.16 round up to 152?? or round down to 151

Haha right 151 :)

Answer 28

what about these 4

Answer 29

Varying Directly

\[\large y = kx\]

Varying Jointly

\[\large y = kxz\]

Varying Inversely

\[\large y = \frac{ k }{ x }\]


Sorry gotta run again....hopefully someone else can help you with this...I'll be back in a bit...

Answer 30

@e.cociuba

Answer 31

which one are you doing?

Answer 32

the very last screen shot i posted

Answer 33

\(y\) varies inversely as \(x\) and \(y=2\) when \(x=25\)
that one?

Answer 34

yes

Answer 35

ok then first step is to write
\[y=\frac{k}{x}\] and find (k\) with \[2=\frac{k}{25}\]

Answer 36

this tells you \(k=50\) and so \(y=\frac{50}{x}\)

Answer 37

now you got to solve
\[40=\frac{50}{x}\] giving \(x=\frac{50}{40}=\frac{5}{4}=1.25\)

Answer 38

so my answer is x=1.25

Answer 39

that is what i get, yes

Answer 40

ok what about the nxt one

Answer 41

@johnweldon1993

Answer 42

please hurry i gtg in a min and this has to be turned in tonight

Answer 43

@satellite73

Answer 44

For that last one you can set up a proportion...you know that distance = rate * time...and they traveled the same distance so

\[\large 40 \space \text{miles per hour} \times .25 \space \text{of an hour} = x \times .33 \space \text{of an hour}\]

so what is 40 times .25? and divide that by the .33 to get...?