Question

In △JKL, KM is an altitude.



What is the length, in units, of JK?

Answer 1

Have u got any related diagram of the question?

Answer 2

just posted it

Answer 3

By using gepmetric mean property we have
\[KM^2 =JM \times ML =5 \times (35-5)=5 \times 30 = 150\]
i.e. \[KM = \sqrt{150}= \sqrt{25 \times 6} =5 \sqrt{6} units\] = 5*2.449=12.245 units

Answer 4

Thank You

Answer 5

Now since KM=5√6 units so condsider triangle JMK use here Pythagoras theorem
we have \[JK^2=JM^2+MK^2 =5^2+ (5\sqrt{6})^2=25+150 =175 \]
\[JK =\sqrt{175} \rightarrow JK = \sqrt{25 \times 7} \rightarrow JK =5 \sqrt{7} units\]

Answer 6

So 5sprt of 7 is the answer