Okay, how do I calculate the slope of the line that passes throught the points (-2,-5) (5,8) I know how solve this when it comes to it being on a graph, I also know for this I need the formula m=y2 -y1 x2 - y1
first you would calculate the slope using the formula \[8-(-5)\over5-(-2)\]
then you would get this\[13 \over 7\]
So, are you dividing or multiplying the numbers?
i believe you misplaced some values ...
or im seeing it off a little .... i dont do the formula that well
(2,5) (5,8) ---- 7,13 your right
I'm confused. How did you get 7 and 13? What did you multiply/divide together? Do you cross multiply/divide or divide/multiply what's next to each other?
you subtract what it tells you to subtract ... the formula is already setup as a fraction
Oh. .-. I forgot there was a subtract sign.
if you want a different approach .. move the points so that one of them is at the origin
(-2,-5) (5, 8) +2+5 +2+5 -------------- 0 0 7 13; slope = y/x ... 13/7
i tend to place the wrong numbers into the wring places if i have to use the formula ... this just makes it idiot proof for me :)
Okay, the other problem I'm on now is Choose the correct slope of the line that passes through the points (0, 0) and (3, 30). so it would be 30 - 0 --------- 3 - 0 Then after that, I simply it, and I get 10?
correct
Can I ask 1 more question?
i just remember it like this:|dw:1374694683170:dw|
Ah, that does seem a bit simpler than the original.
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