Question

check out attachment

Answer 1

@ChinaGurl

I'm looking at this graph.

Do you read from the graph that the x-intercepts to be (-13,0) and (13,0) and
the y-intercepts are (0,6) and (0,-6) ?

Answer 2

@nocontact115

What's up with this mathway.com link? I don't see anything there that is related to this problem. That is, not at the link you posted.

Answer 3

yes. I noticed but I didn't know what step to do next
@Directrix

Answer 4

oh it is to help with any kind of math problem... that is the first place i go towhen i have trouble with math

Answer 5

i'm guessing its A or B

Answer 6

@ChinaGurl
I agree. Let's see if we can eliminate one of those two options.

Answer 7

ok

Answer 8

If you take the equation x^2/13^2 + y^2/6^2 = 1 and substitute 0 for x, then

0^2/ 13^2 + y^2/6^2 = 1

y^2/6^2 = 1

y = 6 or - 6

@ChinaGurl Is that consistent with the graph?

Answer 9

@ChinaGurl

Take If you take the equation x^2/13^2 + y^2/6^2 = 1 and substitute 0 for y, see if you get 13 and -13. Let me know.

Answer 10

I got 13
& -13

Answer 11

Alrighty, then. That confirms that of the options A and B, the correct option is NOT B.

Answer 12

thanks directixxxx! :)

Answer 13

You are welcome.