Question

what happens when comparing a string to an int?
How python will evaluate the test? For instance
'32'>62 is False or True
Thank you

Answer 1

It will throw an exception.

>>> '32'>25
Traceback (most recent call last):
File "<string>", line 301, in runcode
File "<interactive input>", line 1, in <module>
TypeError: unorderable types: str() > int()

Easy enough to test that in IDLE, PyScripter, etc. In contrast:

>>> '32'>str(25)
True

Answer 2

Thank you

Answer 3

np. Have fun!

Answer 4

hmm....
>>> 25 > '35'
False
>>> '35' > 25
True
>>>
Python 2.7.4 (default, Apr 6 2013, 19:54:46) [MSC v.1500 32 bit (Intel)] on win32

Answer 5

Python 3.3.2 (v3.3.2:d047928ae3f6, May 16 2013, 00:03:43) [MSC v.1600 32 bit (Intel)] on win32
Type "copyright", "credits" or "license()" for more information.
>>> 25 > '35'
Traceback (most recent call last):
File "<pyshell#0>", line 1, in <module>
25 > '35'
TypeError: unorderable types: int() > str()
>>>


2.6.5 also acts the way 2.7.4 did. So looks like it is one of those things they are tightening up in the typing system. Python is supposed to be strongly but dynamically typed.

http://wiki.python.org/moin/Why%20is%20Python%20a%20dynamic%20language%20and%20also%20a%20strongly%20typed%20language