Question

Hey all!
Can someone help me out with my studyplan? I want to get this!
How do I write 64^-2/3= in radical notation?
And then evaluate the expression?

Answer 1

\[a ^{\frac{ m }{ n }} = \sqrt[n]{a ^{m}}\]

that's a power law. Try that.

Answer 2

:( thanks but, not it.

Answer 3

\(\bf a^{\frac{n}{m}} = \sqrt[m]{a^n}\\
a^{-n} = \cfrac{1}{a^n}\)

Answer 4

What do you mean can't you do...\[64^{\frac{ -2 }{ 3 }} = \sqrt[3]{64^{-2}}\]

Answer 5

\(\huge a^{-\frac{n}{m}} =\cfrac{1}{\sqrt[m]{a^n}} \)

Answer 6

oh wait - I think I put it in wrong...sorry..I hate this

Answer 7

hmmm still not taking it

Answer 8

Alright try this \[\frac{ 1 }{ \sqrt[3]{64^{2}} }\]

Answer 9

ugh, it says to write it in radical notation - do not evaluate

Answer 10

simplified I get a/64

Answer 11

I did write it In radical form... I didn't simplify. Do you know what radical form is?

Answer 12

the sq rt symbol

Answer 13

I do not know why it will not tajke it

Answer 14

Be careful and try again.

Answer 15

I got it..I wasn't putting the power of 2 in....thank you so much!

Answer 16

good job well done.!

Answer 17

Thanks again - this study plan is killing me.