Question

what is the value of the y variable in the solution to the following system of equations? 3x-6y=12 and -2x+3y=6

Answer 1

multiply the second equation with 2 then solve y will be canceled you get x then sub x in any equation you will get 'y'

Answer 2

Either that or multiply the first equation by 2 and the 2nd by 3....this will cancel the 'x' variable and let you solve for 'y' directly...

2(3x-6y=12)

so this becomes

6x - 12y = 24

and

3(-2x+3y=6)

so this becomes

-6x + 9y = 18

So now we combine our 2 equations


6x - 12y = 24
+(-6x + 9y = 18)
-----------------
0 -3y = 42

so we have

-3y = 42

Divide both sides by -3 to solve for 'y'

-3y = 42
---------
-3 -3


y = 42/-3

y = ???

Answer 3

so y is -14?

Answer 4

That would be correct! :)

Answer 5

Thank you :)

Answer 6

Anytime :)