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What is the vertex in the quadratic function y= -4x^2+8x-3? Write answer as an ordered pair.
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Well you have an equation in the form \[\large ax^2 + bx + c\] To find the x-coordinate of the vertex...you use the equation \[\large \frac{-b}{2a} \] What do you get when you do that?
y = -4x^2+8x-3 y = -4 (x^2 - 2x)-3 y = -4 ((x - 1) ^2 -1)-3 y = -4 (x - 1) ^2 +1 Vertex (1, 1)
no reason to change form when you have -b/(2a)
True, but you should practice you algebra instead of memorizing esp in the beginning. This form gives more than just vertex
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