Question

divide (x^3-y^3) by (x-y)

Answer 1

First, factor (x^3-y^3). One of the factors of (x^3-y^3) will divide out with the (x-y)

Answer 2

can u show me the solution @Directrix ? thanks so much for help..

Answer 3

I am attaching a chart about the factoring pattern for the sum and difference of two cubes. Look at it and then I will help you with the solution.

Answer 4

thank you...

Answer 5

(x^3-y^3) = (x - y) ( x^2 + xy + y^2)

Answer 6

[ (x^3-y^3) ]/ (x-y) =

[(x - y) ( x^2 + xy + y^2)] / (x - y) =

x^2 + xy + y^2 --> This is the quotient, the answer.

The (x-y) factors in the numerator and the denominator divided out.

On the factoring of x^3 - y^3, that is just one of those things you use until you know and recognize it.

Answer 7

Questions?

Answer 8

ur great.. thanks for the big help... :)