divide (x^3-y^3) by (x-y)

Question

divide  (x^3-y^3) by (x-y)

directrix · Answer

First, factor (x^3-y^3). One of the factors of (x^3-y^3) will divide out with the (x-y)

anonymous · Answer

can u show me the solution @Directrix ? thanks so much for help..

directrix · Answer

I am attaching a chart about the factoring pattern for the sum and difference of two cubes. Look at it and then I will help you with the solution.

anonymous · Answer

thank you...

directrix · Answer

(x^3-y^3) = (x - y) ( x^2 + xy + y^2)

directrix · Answer

[ (x^3-y^3) ]/ (x-y) = 

[(x - y) ( x^2 + xy + y^2)] / (x - y) =

 x^2 + xy + y^2 --> This is the quotient, the answer.

The (x-y) factors in the numerator and the denominator divided out.

On the factoring of x^3 - y^3, that is just one of those things you use until you know and recognize it.

directrix · Answer

Questions?

anonymous · Answer

ur great.. thanks for the big help...  :)