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Mathematics 19 Online
OpenStudy (anonymous):

-2√5x3√15

OpenStudy (ivettef365):

that would be (-2)(3) and \(\sqrt{5}\) x \(\sqrt{15}\)

OpenStudy (anonymous):

-30sqrt3?

OpenStudy (ivettef365):

that is -6\(\sqrt{75}\)

OpenStudy (ivettef365):

and yes that is correct

OpenStudy (anonymous):

sqrt 9a over sqrt 3b

OpenStudy (anonymous):

first step plz

OpenStudy (ivettef365):

you said it -30\(\sqrt{3}\)

OpenStudy (anonymous):

new prob

OpenStudy (anonymous):

plz first step

OpenStudy (ivettef365):

ok, so you have \(\sqrt{9a}\) / \(\sqrt{3b}\) is that right

OpenStudy (anonymous):

yes divide is over

OpenStudy (anonymous):

describe first step

OpenStudy (ivettef365):

ok so \(\sqrt{9a}\) = 3\(\sqrt{a}\) right

OpenStudy (anonymous):

solve for x √x+3 = 4

OpenStudy (anonymous):

please

OpenStudy (ivettef365):

so did you get the answer

OpenStudy (anonymous):

new prob

OpenStudy (ivettef365):

it is 3\(\sqrt{a}\) / \(\sqrt{3b}\)

OpenStudy (anonymous):

Nevermind i got it its 13

OpenStudy (ivettef365):

so the problem is \(\sqrt{x+3}\) = 4

OpenStudy (anonymous):

Thanks for your time tho

OpenStudy (ivettef365):

so the first step is to square both sides you have (\(\sqrt{x+3}\) )^2 = (4)^2

OpenStudy (ivettef365):

that is equal to x + 3 = 16 now you can solve for x

OpenStudy (ivettef365):

no problem

OpenStudy (anonymous):

i have more questions that i will ask so feel free to answer them haha

OpenStudy (ivettef365):

I have to go for a few minutes, be back

OpenStudy (anonymous):

ight

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