Mathematics
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OpenStudy (anonymous):
-2√5x3√15
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OpenStudy (ivettef365):
that would be (-2)(3) and \(\sqrt{5}\) x \(\sqrt{15}\)
OpenStudy (anonymous):
-30sqrt3?
OpenStudy (ivettef365):
that is -6\(\sqrt{75}\)
OpenStudy (ivettef365):
and yes that is correct
OpenStudy (anonymous):
sqrt 9a over sqrt 3b
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OpenStudy (anonymous):
first step plz
OpenStudy (ivettef365):
you said it -30\(\sqrt{3}\)
OpenStudy (anonymous):
new prob
OpenStudy (anonymous):
plz first step
OpenStudy (ivettef365):
ok, so you have \(\sqrt{9a}\) / \(\sqrt{3b}\)
is that right
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OpenStudy (anonymous):
yes divide is over
OpenStudy (anonymous):
describe first step
OpenStudy (ivettef365):
ok so \(\sqrt{9a}\) = 3\(\sqrt{a}\) right
OpenStudy (anonymous):
solve for x √x+3 = 4
OpenStudy (anonymous):
please
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OpenStudy (ivettef365):
so did you get the answer
OpenStudy (anonymous):
new prob
OpenStudy (ivettef365):
it is 3\(\sqrt{a}\) / \(\sqrt{3b}\)
OpenStudy (anonymous):
Nevermind i got it its 13
OpenStudy (ivettef365):
so the problem is \(\sqrt{x+3}\) = 4
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OpenStudy (anonymous):
Thanks for your time tho
OpenStudy (ivettef365):
so the first step is to square both sides you have
(\(\sqrt{x+3}\) )^2 = (4)^2
OpenStudy (ivettef365):
that is equal to
x + 3 = 16 now you can solve for x
OpenStudy (ivettef365):
no problem
OpenStudy (anonymous):
i have more questions that i will ask so feel free to answer them haha
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OpenStudy (ivettef365):
I have to go for a few minutes, be back
OpenStudy (anonymous):
ight