Question

can someone show me how to do this please look at the picture

Answer 1

i thought it would be x^2+x^2/3-6=36 but i was wrong

Answer 2

@Mertsj

Answer 3

Did you factor the number?

Answer 4

Sorry I meant the expression.

Answer 5

Replace x^2 with 3y+18

Answer 6

for which one @Mertsj

Answer 7

well, according to the second equation x^2=3y+18 so you would have to put it into the first equation.

Answer 8

3y+18+y^2=36

Answer 9

-6,3?

Answer 10

Those are the y values. Now you have to find the x values.

Answer 11

so do i plug the -6,3 into the second equation?

Answer 12

yes. or the first. It does not matter.

Answer 13

i keep getting no solution

Answer 14

Post what you did and I will trouble shoot it.

Answer 15

-6^2+3^2=36

Answer 16

good

Answer 17

So here is your problem. When you solved that equation and got -6,3 those were y values. You should have written y = -6 or y = 3

Answer 18

So you cannot use either one of those as replacements for x because they are y values.

Answer 19

You must choose one of them and plug it in in place of y and then solve for x.

Answer 20

After you do that, then take the other one, plug it in in place of y and solve for x again.

Answer 21

i got x=0 from the second equation using -6

Answer 22

Me too. So one solution is (0,-6)
Now plug in 3

Answer 23

3 is not working for me

Answer 24

\[3+6=\frac{1}{3}x^2\]
\[9=\frac{1}{3}x^2\]

Answer 25

Multiply both sides by 3 and then take the square root of both sides.

Answer 26

1/3 cancels out right? leaving just 9?

Answer 27

Multiply BOTH SIDES by 3

Answer 28

27 1/6 ? idk what im doing!

Answer 29

1/9 i mean