Evaluate cot 45° without using a calculator by using ratios in a reference triangle.
im totally lost
@phi can u plz help, thanks
do any of u know how to solve?
you need to take tHe referene triangle:|dw:1374863817741:dw| THe Cot of 45 is te same as 1/tan(45) wiCH is tHe Hypotenuse/adjaent or \[\cot (45)=\frac{ 1 }{ \tan (45) }=\frac{ Hyp }{ adj }=\frac{ \sqrt{2} }{ 1 }=\sqrt{2}\]
@ivancsc1996 it should be cot = adj/opp, since tan is opp/adj.
OH you are rigHt
cot = x/y = cos/sin? right?
tHen tHe answer is 1
Correct, cot = cos/sin
and cos and sin are both 45 right?
no, tHey are BotH 1
No, cos45 = sin45 = sqrt2/2
When you divide them, you get 1.
YEaH wHat He said
so its (sqrt2/2)/(sqrt2/2)
which becomes sqrt/2 * 2/sqrt
which then cancels to 1 right?
NO, it is \[\frac{ \frac{ 1 }{ \sqrt{2} } }{ \frac{ 1 }{ \sqrt{2} } }=\frac{ \cos 45 }{ \sin 45 }=\cot 45\]
huh
@agent0smith could u explain
Yes, cot45 = 1, just like tan45=1.
how do u get there though
i need to see hoe u got there
Get cos and sine from the triangle (or use tan): cos45 = 1/sqrt2 sin45 = 1/sqrt2 cot45 = 1/tan45 tan45 = (1/sqrt2)/(1/sqrt2) = 1 so cot45 = 1/tan45 = 1/1 =
why 1/sqrt 2
Because cos is adj/hyp... look at the triangle.
why r the side lengths 1
cos45 = 1 / sqrt2 sin45 = 1 / sqrt2 cot45 = cos / sin cot54 = (1/sqrt2)/(1/sqrt2) = 1/1 = 1
is that a good explanation
The side lengths have to both be 1 with a right angle so that it's isosceles, and will have 45 degree angles.
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