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Mathematics 22 Online
OpenStudy (anonymous):

picture of question is posted...

OpenStudy (anonymous):

OpenStudy (anonymous):

@genius12

OpenStudy (anonymous):

@ybarrap

OpenStudy (anonymous):

when they say, "shows a 4", does that mean 4 is one of the numbers rolled or that 4 is the outcome???

OpenStudy (anonymous):

Once again 36 total outcomes. Outcomes we're looking for have a '4' and the sum of 4 + x, 'x' being the other number you roll, has to be even. So basically:\[\bf 4+x=2k \implies x = 2k-4\]We know that x = 2k-4 is greater than 0 as you can't roll a number smaller than 0:\[\bf 0 < 2k-4 \le 6 \implies 4 < 2k \le 10 \implies 2 < k \le 5\]So for integer values of 'k' from this inequality we get that k equals 3, 4, 5. Plugging these values of k back in to x = 2k-4 we get :\[\bf x = 2,4,6\]Each of these numbers produces a combination with 4 that has an even sum in 2 (except for 4,4) ways: (2,4),(4,2),(4,4),(4,6),(6,4. That's a total of 5 ways out of 36. So the probability is? @music101

OpenStudy (anonymous):

5/36??

OpenStudy (anonymous):

Correct.

OpenStudy (anonymous):

@music101 Good job.

OpenStudy (anonymous):

so again: when they say, "shows a 4", does that mean 4 is one of the numbers rolled or that 4 is the outcome???

OpenStudy (anonymous):

thnks:)

OpenStudy (anonymous):

eXACTLY

OpenStudy (anonymous):

4 IS ONE OF THE NUMBERS ROLLED.

OpenStudy (anonymous):

thats what it means. @music101

OpenStudy (anonymous):

woow. so not the outcome right??

OpenStudy (anonymous):

yup, when they say you roll a 4 and an even sum they mean that one of the numbers rolled is a 4, and one of the other numbers rolled forms an even sum with 4. So like 4,6 or 2,4 both have 4 rolled in them and add up to an even number. @music101

OpenStudy (anonymous):

I was telling satellite that but he told me that its the outcome... :( so what if this exact problem said " the sum is odd or 1 die sows a 5"???

OpenStudy (anonymous):

*shows

OpenStudy (ybarrap):

i kinda like to start with one die, say the 4 and see what the other needs to give me an even number, I count 2,4 and 6, that's 3. But then do that in reverse, that is, if the other die is a 4 then the 1st can be a 2,4 or 6, but be careful with the (4,4) case -- don't count it twice. In many cases, you can proceed like this. 5/36 is correct.

OpenStudy (anonymous):

no im talking abt this question I just asked

OpenStudy (anonymous):

what if it was " the sum is odd or 1 die shows a 5"?

OpenStudy (anonymous):

would it be: 5,2 2,5 5,6 6,5

OpenStudy (ybarrap):

Start with 5, the other die possibilities would be 2,4, 6, now do the reverse. Because (5,5) is not a possibility, there are now 6 ways to get an odd sum with one die a 5.

OpenStudy (anonymous):

ok..

OpenStudy (anonymous):

then?

OpenStudy (ybarrap):

so prob is 6/36 or 1/12 for this last case

OpenStudy (ybarrap):

you left out 4,5 and 5,4 as possibilities

OpenStudy (anonymous):

oops that too

OpenStudy (anonymous):

no wait that's not a prime sum though

OpenStudy (ybarrap):

I meant 6/36 or 1/6 not 1/12

OpenStudy (anonymous):

yeah but u didn't count 5,4 and 4,5 right

OpenStudy (anonymous):

hello?

OpenStudy (anonymous):

@genius12 @ybarrap pls! I have to finish these ASAP!

OpenStudy (anonymous):

@mary.rojas

OpenStudy (mary.rojas):

question?

OpenStudy (anonymous):

@music101 Sorry I had to leave. Are you still here?

OpenStudy (anonymous):

@music101 You still have a question??

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