The following equation is what I'm working on 12x^3-28x^2+3x-7, I came up with the following answer 4x^2(x-7)(3x+7). Can someone tell me if I got it right, if not can you pls assist me?

Question

anonymous · Answer

its not an equation

anonymous · Answer

technically thats an expression

anonymous · Answer

oh ok now I know for the future... thx.

anonymous · Answer

i mean... equations are supposed to have an = sign
expressions do not
and yes it looks good

anonymous · Answer

wait

anonymous · Answer

the first term

anonymous · Answer

you factored the 4 incorrectly

anonymous · Answer

Basically you are trying to factor by grouping. You have the following polynomial:$$\bf 12x^3-28x^2+3x-7$$Factor $\bf 4x^2$ from first two terms:$$\bf 4x^2(3x-7)+3x-7$$We can re-write this as:$$\bf 4x^2(3x-7)+1(3x-7)$$Since both share (3x-7), we can factor it out and the final factored form becomes:$$\bf 12x^3-28x^2+3x-7=(4x^2+1)(3x-7)$$

anonymous · Answer

@xander0327

anonymous · Answer

i if i am not making any mistake i think that is it

anonymous · Answer

ehh you kinda just gave the answer 
@genius12

anonymous · Answer

btw how do you get that bold print ?

anonymous · Answer

@mth3v4 I showed him how to do it. Didn't just give the answer. From his answer I knew he was on the right track, showing him the rest of the way should probably fix his issues.

@mth3v4 Type "bf" without the quotes in the equation editor before the rest of the expression/equation. "bf" stands for boldface.

anonymous · Answer

suspects some super smart person to bonk me  in the head*

anonymous · Answer

:P

anonymous · Answer

Genius12 Thanks for the assistance I appreciate it. That does look like what I was missing, I just wasn't sure about mine and it didn't look right. Thx again.

mth3v4 thank you too, for giving it a shot.