concept of probabilty
Let P(Z)=.40, P(Y)=.30, and P(Z∪Y)=.58 Find each of the given probability
a,,P(Z'∩Y') @alexwee123
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
@payin Are Are Z' and Y' the respective complements?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
@genius12
OpenStudy (anonymous):
@payin
OpenStudy (anonymous):
I was able to derive that formula from the following:\[\bf P(Z' ∪ Y')=P(Z')+P(Y')-P(Z'∩Y')\]\[\bf \implies P(Z'∩Y')=P(Z')+P(Y')- P(Z' ∪ Y')\]
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
@payin Do you see what I did?
OpenStudy (anonymous):
@payin Just a second I made a mistake. Let me correct myself.
OpenStudy (anonymous):
yeah i did
but im tryna figure out how u got those figures
OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
The formula that I just typed in is correct. I just plugged in the wrong values for P(Z'∪Y'). Let me type up the correct solution.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
We know P(Z) = 0.4 then P(Z') = 1 - 0.4 = 0.6
Similarly P(Y) = 0.3 then P(Y') = 1 - 0.3 = 0.7
Now saying P(Z'∩Y') is the same as saying probability of Z' and Y' which is:\[\bf P(Z'∩Y')=0.6 \times 0.7 = ?\]
@payin