Find the probability of rolling a sum of five with a single toss of two fair six-sided dice.
@Hero
Okay...
??
is it 1/6
what so i do count all the dice that have 6
There are 36 possible pairs, and of those, there are four pairs that sum to five
So the probability of rolling a sum of five with two six-sided dice is \[\frac{4}{36} = \frac{1}{9}\]
so its1/9 what about this one Find the probability of getting one head and two tails on a toss of three fair coins
The same logic applies. Find the total possible pairs, then find how many of those have one head and two tails.
It's only three coins so you can probably do it with pencil and paper.
here's how I figured out the previous one: Notice how I circled those that add to five.
would it be 1/8
HHH HHT HTH `HTT` THH `THT` `TTH` TTT
There are eight possible pairs, and of those, three of them have meet our requirements.
so 1/3 would be the correct answer
\[\text{probability} = \frac{\text{no of occurrences}}{\text{total possible outcomes}}\]
There are eight possible outcomes, of those only three of the expected event occurs.
ohh wow its 3/8 lol can you help me on this one too If we roll two dice 180 times, how many times can we expect the dice to show a sum of five? 5 20 45 36
I can only help you so much before you'd be expected to start figuring these out on your own.
is it the same for this one the way you did it before
Here, solve this proportion: \[\frac{4}{36} = \frac{x}{180}|\] It's not the same approach.
x=20
Good
ok i think i get it now :)
You'd have to prove to me that you get any of this.
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