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|dw:1374945138000:dw|
Is your question as given below? \[\frac{1}{9}-\frac{5}{3a}=\frac{1}{3}\]
yes
Ok so wait
oh sorry the 1/9 is actually 1/a
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\[\frac{1}{a}-\frac{5}{3a}=\frac{1}{3} \rightarrow \frac{3a-5a}{3a \times a}=\frac{1}{3}\] \[ \frac{3a-5a}{3a \times a}=\frac{1}{3} \rightarrow 3(-2a)=3a^2 \rightarrow-2a= a^2\] \[-2a= a^2 \rightarrow -2 = \frac{a^2}{a} \rightarrow -2=a \] or a=-2
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