Question

show the following .pls

Answer 1

Re\[ \left\{ \sin ^{-1} \right\}=\frac{ 1 }{ 2 }\left\{ \sqrt{x ^{2}+y ^{2}+2x+1} \\-\sqrt{x ^{2}+y ^{2}-2x+1}\right\}\]

Answer 2

Question not complete.

Answer 3

it is \[\sin ^{-1}z\]

Answer 4

\(\bf \large sin ^{-1}(\square?) =\cfrac{ 1 }{ 2 } \pm\sqrt{x^2+y^2+2x+1} \ \ ?\)

Answer 5

Where did y come from?

Answer 6

i think z is complex

Answer 7

then \[z=x+yi\]

Answer 8

don't forget that Re is real in complex

Answer 9

@phi

Answer 10

@walters Can you post the problem from scratch and everything that has to do with it?

Answer 11

ok give a minute

Answer 12

Show that Re\[ \left\{ \sin ^{-1} z\right\}=\frac{ 1 }{ 2 }\left\{ \sqrt{x ^{2}+y ^{2}+2x+1}\\-\sqrt{x ^{2}+y ^{2}-2x+1} \right\}\]

Answer 13

this is hoe the question is so since i am working with complex numbers i think \[z=x+yi\]

Answer 14

I don't think that is correct. The solution contains some natural logs.
Are you sure z = x + yi?

Answer 15

i am not sure this is i was thinking since we are in complex numbers

Answer 16

so wat is?

Answer 17

It's really ugly if z = x+yi. Very long.

Answer 18

so do u have any idea how to do it

Answer 19

It all depends on what z equals.

Answer 20

can u show me how long can it be?

Answer 21

Wait, just the real part?

Answer 22

Yes, it is correct.

Answer 23

so can u help