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Mathematics 26 Online
OpenStudy (xochital):

could someone help me with simplifying radicals

OpenStudy (xochital):

& multiplying radicals?

OpenStudy (austinl):

I can do my best. Lets see what you need help with.

OpenStudy (xochital):

the equation is: multiply \[5\sqrt{8} * 4\sqrt{7}\]

OpenStudy (anonymous):

It's 40sqrt14

OpenStudy (xochital):

could you explain how you did it?

OpenStudy (austinl):

We try and guide to answers here, not just give them. You multiply the values out of the square root. 5*4=20 And inside, 7*8=56 \[20\sqrt{56}\] \[20\sqrt{4\times 14}\]

OpenStudy (anonymous):

\[40\sqrt{14}\]

OpenStudy (anonymous):

I used a scientific calculator lol

OpenStudy (anonymous):

sure. first, you multiply the similar elements. so: 5 x 4 x sqrt(8x7) That becomes 20 sqrt56 and then you simplify and get 40sqrt14

OpenStudy (jdoe0001):

@xochital if the roots are the same, that is square or cube or else then you multiply the OUTSIDE by the OUTSIDES and the INSIDE by the others INSIDES

OpenStudy (austinl):

\[\sqrt{4} = 2\] and you move that outside the square root. \[20\times 2\sqrt{14} = 40\sqrt{14}\]

OpenStudy (anonymous):

yeah, true @austinL. It's just preference that I give the answer first.

OpenStudy (xochital):

thank you all so much :)

OpenStudy (austinl):

No problemo!

OpenStudy (xochital):

so would \[\sqrt{3} * \sqrt{5}\] ?

OpenStudy (xochital):

that would equal \[\sqrt{15}\] or something else ?

OpenStudy (austinl):

\[\sqrt{3}\times \sqrt{5}=\sqrt{3\times 5}=\sqrt{15}\] Correct.

OpenStudy (xochital):

okay, do you mind helping me with a few more?

OpenStudy (austinl):

Sure, I don't mind at all.

OpenStudy (xochital):

okay thank you so much. for \[5\sqrt{3}(2\sqrt{3}+6\sqrt{19})\] would i have to distribute the \[5\sqrt{3}\]

OpenStudy (austinl):

Yes you would. a(b+c) = ab + ac

OpenStudy (xochital):

then it would be ... \[10\sqrt{9}*30\sqrt{57}\].... how would i simplify that?

OpenStudy (austinl):

First, sqrt(9) = ?

OpenStudy (xochital):

3

OpenStudy (austinl):

Correct.10*3=30

OpenStudy (austinl):

\[30 + 30\sqrt{57}\] The second half cannot be simplified.

OpenStudy (xochital):

oh okay... how would i solve \[3x \sqrt{2}*\sqrt{14x}\]

OpenStudy (austinl):

\[3x\sqrt{2\times 14x} = 3x\sqrt{28x}\] \[\sqrt{28} = 2\sqrt{7}\rightarrow3x\times2\sqrt{7} = 6x\sqrt{7x} = 6x\sqrt{7} \times x^{\frac{1}{2}} = 6\sqrt{7}\times x^{\frac{3}{2}}\]

OpenStudy (xochital):

one of the choices is \[6x \sqrt{7x}\] that's the correct answer then, right?

OpenStudy (austinl):

Well, then that is it. I went further than your question required I guess :P

OpenStudy (xochital):

hahha yes i guess you did :) one last question... \[\sqrt{2}(x-\sqrt{5})\]

OpenStudy (xochital):

would it be \[\sqrt{2x} - \sqrt{10}\]?

OpenStudy (xochital):

and then if i simplified that further it would come to \[\sqrt{2x} - \sqrt{5}\] or did i do that completely wrong? lol

OpenStudy (austinl):

No it would not be. You can only multiply numbers by numbers, and radicals by radicals.

OpenStudy (austinl):

\[x\sqrt{2} - \sqrt{10}\]

OpenStudy (xochital):

oh okay, that makes sense! thank you so much :) this helped a lot, i appreciate it.

OpenStudy (austinl):

No problem!

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