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Suppose that △ABC is a right triangle with ∠C=90∘. If AC=4 and BC=6, find the following quantities. cosA sinA tanA secB cscB cotB
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draw a diagram |dw:1374959431390:dw| when you know AB you can find your trig ratios
4sqrt3
cosA=4/4sqrt3?
so the hypotenuse AB seems to be incorrect \[AB^2 = 36 + 16...so...AB^2 = 52..... or.... AB = 2\sqrt{13}\] which affects all your answers.
so cosA=4/2sqrt13?
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thats correct
ok thanks
how would i get the sec csc and cot
for remember sec = 1/cos csc = 1/sin cot = 1/tan so find the ratios sin, cos tan then take the reciprocals.
k thanks
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but its secB and not secA
sin find cosB then take the reciprocal of that answer...
thanks
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