log 3 5 + log 3 x = log 3 10
no the threes are at the bottom of the log
\[\log_3(5) + \log_3(x) = \log_3(10)\]
yes Thank you @Hero
Remember \(\log(a) + \log(b) = \log(ab)\)
log x + log (x+3) = log 10 log x(x+3) = log 10 x(x+3) = 10 x^2 + 3x = 10 x^2 + 3x - 10 = 0 (x-2)(x+5) = 0 x = 2 or x = -5
u think u smart @50_cent
\(\bf \log_3(5) + \log_3(x) = \log_3(10)\\ log_3(5\times x) = \log_3(10)\\ \text{log cancellation rule of}\\ a^{log_ax} = x\\ 3^{log_3(5\times x)} = 3^{\log_3(10)} \implies 5x = 10\)
im so smart
@50_cent steps are not correct
then show me hero
hahahaha but seriously hero how i do this junk
The steps are pretty simple \[\log_3(5) + \log_3(x) = \log_3(10) \\ \log_3{(5x)}=\log_3(10) \\5x = 10\]
Solve for x
ohhhhhhhhhhhh forgot to put 5 x
@50_cent, your steps are simply not correct.
@jdoe0001 did extra steps that were unnecessary.
ohh
OMG @Hero
so x=2
Correct. Don't forget to check.
ok can u help me with a few more
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