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Use trigonometric identities to simplify the trigonometric expression (cscx+cotx)(cscx-cotx)
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Well first, we recall that \[\large (a+b)(a-b) = a^2 - b^2\] Analogous to this, what would be your first step in simplifying?
umm would I start by dividing
No :) Just recall this: \[\large (a+b)(a-b) = a^2 - b^2\] The product of the sum and difference of two numbers is the difference of their squares... It's like your a = csc(x) and b = cot(x) Now, do the first step in simplifying...
canceling out right?
What cancels out?
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(a-b)
maybe?
use the hint @terenzreignz provided "a = csc(x) and b = cot(x)"
|dw:1374982770407:dw|
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