Which of the following is the minimum value of the equation y=3x^2-4x-2 A. -2/3 B.2 C.3 D. -3 3/3
-b/2a is the equation for the axis of symmetry. When you solve for -b/2a, the number you get will be an x-coordinate. Just plug that x value into the equation and solve for y.
I dont know what numbers to put in for -b/2a
Ah, okay. Well, when you get these equations with x^2 in them, they have a general form of ax^2 + bx + c. Basically, your b is the number paired with x and a is the number paired with x^2.
so its -4/2(3)
Almost. B is already -4. So it'd be -(-4)/(2)(3).
it would b 6
be
6 would be the denominator. You'd have 4/6 which reduces to 2/3.
Also, what is option D supposed to be?/ 3 3/3 doesn't look right.
*-3 3/3
-3 1/3
Okay, makes more sense then :3
so its D.
Yep. You get 2/3 once you solve for -b/2a, then once you plug it in you get a y-value of -10/3 or just -3 1/3
thank you
np
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