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Mathematics 19 Online
OpenStudy (anonymous):

Integral Question! Thanks in advance!

OpenStudy (anonymous):

OpenStudy (bahrom7893):

integrate that from 0 to 4

OpenStudy (anonymous):

but the equation at t=0 doesn't equal 70 so I'm confused or does that not matter? @bahrom7893

OpenStudy (bahrom7893):

No that's the rate of how the increase. You need the actual increase.

OpenStudy (anonymous):

I got 916.8 but that was incorrect when I put in the answer

OpenStudy (anonymous):

@bahrom7893

OpenStudy (anonymous):

@FutureMathProfessor is there anyone you can help? I've gotten the same answer multiple times and I can't figure out what I'm doing wrong

OpenStudy (anonymous):

solve as a differential equation rather than an integral. \[\frac{ dP }{ dt } = 210 + 8t + 0.6t^2\] \[\int\limits_{}^{} dP = \int\limits_{}^{} 210 + 8t + 0.6t^2 dt\] \[P(t) = 210t + 4t^2 + 0.2t^3 + C\] given in question that P(0) = 70 --> plugging this in above gives C = 70 so your solution is now: \[P(t) = 210t + 4t^2 + 0.2t^3 + 70\] plug in 4 in P(t)

OpenStudy (anonymous):

@Euler271 I've also tried that and it was incorrect as well :(

OpenStudy (anonymous):

what is the answer?

OpenStudy (anonymous):

I don't have it I have 7 attempts remaining

OpenStudy (anonymous):

my method gives 986.8 another "method" i jotted down gives 321.6. you should try 986.8 first though

OpenStudy (anonymous):

I have tries 986.8 986 and 987 I have also tried 916.8 916 and 917 none are correct this is a pain thank you for attempting to help me

OpenStudy (anonymous):

321.6 was also incorrect

OpenStudy (anonymous):

no problem webwork isn't necessarily right btw. i went nuts one night lol

OpenStudy (anonymous):

I know it isn't! It is just frustrating when I have done my homework and understand it but don't get a 100 on it :( haha thanks for your help though

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