Please help!!! Identify the points corresponding to P and Q. A.P'(0, 4), Q'(–1, 7) B.P'(-1, 4), Q'(–3, 7) C.P'(0, 4), Q'(–3, 7) D.P'(-1, 4), Q'(1, 7)
@satellite73 can you help me please Ive been stuck for an hour
@dumbcow can you please help me?
what's the transformation?
I'm not sure I just learned this @pgpilot326
you're giving incomplete info
I have a graph in the attachments
yes, i know. you still haven't given all of the info needed. P is at (-2, 4) and Q is at (1, 7). None of the answers match and they're given in terms of P' and Q' which are generally points which have been transformed from some original position.
I'm sorry but these are the only answer choices I have, But it does look pretty weird thats why I asked the question on here. P'(0, 4), Q'(–1, 7) P'(-1, 4), Q'(–3, 7) P'(0, 4), Q'(–3, 7) P'(-1, 4), Q'(1, 7)
@pgpilot326
what's the question being asked?
Identify the points corresponding to P and Q.
and that's all that's given? nothing about a rotation or translation of any kind?
Nope just that, my closest guess is that its D.
But Im really not sure
good luck. something is goofed.
Can you help me with one simliar to this one? please @pgpilot326
what is it?
Which of the following equations describes the graph?
A.y=-1/2x^2-x-2 B.y=1/3x^2-x-2 C.y=1/2x^2-x+2 D.y=-1/3x^2-x+2
look at the graph... when x = 0, y is 2 so it can't be either of the first 2 choices. next, when x = 3, y = 2. Plug in x = 3 to the remaining equations and see which one works.
o ok so the answer is C.
you didin't do the work
yes I did on my sheet of paper
so \[\frac{ 1 }{ 2 }\left( 3 \right)^{2}-\left( 3 \right)= 0?\]
i got -2.9
exactly... but the result needs to be 0 which is why C is not the answer. Try it with D and see what you get.
it was D. it equals 0
Thank you very much
you're welcome
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