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OpenStudy (anonymous):

HELP: find the horizontal limits of the function. (ATTACHED BELOW)

OpenStudy (anonymous):

OpenStudy (anonymous):

@dumbcow

OpenStudy (anonymous):

i got 11/-6

OpenStudy (anonymous):

and im not sure for the other one

OpenStudy (anonymous):

thats correct

OpenStudy (anonymous):

dear by horizontal limit u mean limit in infinite ?

OpenStudy (anonymous):

it doesnt say..

OpenStudy (anonymous):

everything is attached

OpenStudy (anonymous):

Horizantal limit is -11/6

OpenStudy (anonymous):

it says and

OpenStudy (anonymous):

is there 2 answers?

OpenStudy (anonymous):

are*

OpenStudy (anonymous):

i wrote my answers thrre but im not sure if theyre correct

OpenStudy (anonymous):

no the one -11/6 is correct @Roya yes it means take the limit at infinity .

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

yes its right

OpenStudy (anonymous):

thank yoou

OpenStudy (anonymous):

yw :)

OpenStudy (anonymous):

@sami-21 what if it is to -infinity

OpenStudy (anonymous):

is it the same thing?

OpenStudy (anonymous):

considering this you answer is correct .

OpenStudy (anonymous):

what if it say as x approaches to negtive infinity

OpenStudy (anonymous):

its gonna produce similar result because the answer is depending on the coefficients of highest terms in both numerator and denominator .

OpenStudy (anonymous):

lets say for this one. the first one: i got -2

OpenStudy (anonymous):

OpenStudy (anonymous):

but the second question asks: if it's coming from - infinity. @sami-21

OpenStudy (anonymous):

@Roya

OpenStudy (anonymous):

@sami-21

OpenStudy (anonymous):

still -2

OpenStudy (anonymous):

can someone explain why the negative infinity part right?

OpenStudy (anonymous):

@sami-21 i know it's -2 so how do we know it's -2? since i found the infinity part... and to find the negative infinity part would be.. ?

OpenStudy (anonymous):

the same thing?

OpenStudy (anonymous):

there is no different between + or - infinity. while solving these kind of question you ignore other part because infinity is so great. regardless it's positive or negative

OpenStudy (anonymous):

so if i solved for infinity, an it asked me the -infinity, the answer is the same?

OpenStudy (anonymous):

@Roya

OpenStudy (anonymous):

yes the same answer

OpenStudy (anonymous):

oh okay great thanks you

OpenStudy (anonymous):

as i mentioned above these limits depends on the coefficients of the highest terms in both numerator and denominator . lets give it a try divide both numerator and denominator with highest power (here it is simply x ) \[\Large \lim_{x \rightarrow -\infty} \frac{ \frac{4+8x}{x}}{\frac{3-4x}{x}}\] \[\Large \lim_{x \rightarrow -\infty} \frac{\frac{4}{x}+8}{\frac{3}{x}-4}\] apply the limits \[\Large \lim_{x \rightarrow -\infty} \frac{\frac{4}{-\infty}+8}{\frac{3}{-\infty}-4}\] \[\Large \frac{-0+8}{-0-4}=\frac{8}{-4}=-2\]

OpenStudy (anonymous):

just take care of function with different behavior along x axis . I mean the fuction which have different function for each of the X axis part |dw:1375077760801:dw|

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