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The number of solution of log base4 (x-1)=log base2 (x-3) is
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2 values of x
how 2 answers
\[\log_{4}(x-1) = \log_{2}(x-3) \] \[\large x-1 = 4^{\log_{2}(x-3)} \] \[\large x-1 = 2^{2\log_{2}(x-3)}\] \[x-1 = (x-3)^{2}\] now just solve the quadratic...so yes there are 2 solutions
there u go
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