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OpenStudy (aonz):
you sure you got the question right?
OpenStudy (jkbo):
Yup thats the whole question
OpenStudy (aonz):
sure its not 25x^2 - 64?
HanAkoSolo (jamierox4ev3r):
\(25x^2-64\)
@jkbo
OpenStudy (jkbo):
yes @Jamierox4ev3r
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HanAkoSolo (jamierox4ev3r):
oh ok so @AonZ was right then
OpenStudy (mayankdevnani):
\[\huge 25^2=625\]
so we get,
\[\huge 625-64\]
and we can write this as :
\[\huge (25)^2-(8)^2\]
use \(\large a^2-b^2\) identity
and this identity states that:
\[\huge a^2-b^2=(a-b)(a+b)\]
OpenStudy (mayankdevnani):
can you solve it? @jkbo
OpenStudy (jkbo):
yes thank you I found the answer can you help me with one more?
factor 15x^2 + 20x
OpenStudy (mayankdevnani):
@jkbo we can write this in two forms:
\[\huge 1)~~~~ x(15x+20)\]
\[\huge 2)~~~~5x(3x+4)\]
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OpenStudy (mayankdevnani):
understood? @jkbo
OpenStudy (aonz):
well you would always want it it form 2 not 1
OpenStudy (mayankdevnani):
what? i don't understand. @AonZ
OpenStudy (aonz):
form 2 is more correct?
OpenStudy (mayankdevnani):
lol... how would you choose form 2 ? it is impossible .
because in 20x , x is in the form of 1 degree not 2 degree
How would we factorize it in 2 nd form?
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OpenStudy (mayankdevnani):
@AonZ
OpenStudy (aonz):
Huh? your confusing me now?
OpenStudy (mayankdevnani):
lol..... can you factorize it in 2nd form
\[\huge 20x\]
can you?
OpenStudy (aonz):
oh, i meant when u said "we can write this in two forms" then I said number 2 is more correct
OpenStudy (mayankdevnani):
oh!!! all are correct
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OpenStudy (jkbo):
15x +20
OpenStudy (mayankdevnani):
what is this? ^^^
OpenStudy (jkbo):
Thank you
OpenStudy (jkbo):
I was solving the problem
OpenStudy (mayankdevnani):
Ohkk
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