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Mathematics 16 Online
OpenStudy (anonymous):

Solve by elimination 3x + y = 20 x + y = 12

OpenStudy (psymon):

You have to multiply one of the equations in a way that when you add them, one of the variables cancels. Basically, how can you multiply one of your equations so that you have the same x or y in each equation, but one being negative and one being positive? It can be easily done to get y's to cancel in this one.

OpenStudy (anonymous):

do i multiply it by -3

OpenStudy (psymon):

You could multiply the bottom by negative 3 to get rid of x, yes. Also notice you can simply multiplyit by negative 1 to get rid of y. Both work :3

OpenStudy (psymon):

Just make sure you multiply EVERYTHING in the equation by negative 3 or negative 1, including theother side of the equal sign.

OpenStudy (anonymous):

kk dont leave im going to solve it and ask you to see if i am right that okay

OpenStudy (psymon):

alrighty.

OpenStudy (anonymous):

i got (4,8)

OpenStudy (psymon):

Right :3

OpenStudy (anonymous):

thank you

OpenStudy (psymon):

Np.

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