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OpenStudy (anonymous):
an analysis of vinegar showed that 12.4 g of acetic acid, CH3COOH, were present in 248 ml of vinegar sample. The molar concentration if acedic acid in this vinegar is?.
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OpenStudy (aaronq):
(1) convert 12.4 g to moles moles=mass/molar mass then, (2) find the solutions molarity molarity=moles of solute/L of solution
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