Which expression is not equivalent to the other expressions?
a. \[7 + 0.5 \times 4^{2}\] b. \[2.5 \times (16 - 2^{2})\] c. \[(3^{3} + 3) \div 2\] d. \[(20 + 5^{2}) \div 2\]
Did you try simplifying each expression? btw, make sure there are no typos in the question...
until i find the different one right? @phi
what do you get for 7+0.5×4^2 ?
@phi 120
remember order of operations do exponents first, the multiply, then add
7 + 0.5 * 4^2 first do 4^2 which means 4*4. you get 16 7 + 0.5*16 now do the multiply.
@phi \[7+0.5 \times 4^{2} = 120\] \[2.5 \times (16-2^{2}) = 30\] \[(3^{3} + 3) \div 2= 15\] \[(20 + 5^{2}) \div 2= 12\]
the first one is not 120. try again
@phi but the others are right?
last one is wrong also.... and I think there is a typo somewheres. But first things first, what is the first expression ?
@phi hold on I have someone from my family also helping and he wants to know if its d.
what is the first expression ?
7 + 0.5 x 4^2 and if you follow PEMDAS you first do the eponets
@phi
yes, what do you get ?
@phi 16 because 16= 4 x 4
what is 7 + 0.5 x 4^2 ? 4*4 is 16, so now what is 7 + 0.5*16 ?
@phi I did a typo on D. its divided by 3 not 2 and 8 then add 7 and its 15
ok so we have a 15 b 30 c 15 d (20+5^2)÷3 = (20+25)/3 = 45/3 = 15 which one is different ?
b. ... oh i get it ty for correct me!
this question tested if you know Order of operations (Can you follow rules ?)
@phi yes I love order of operation im very good at it but when im not focused not at all
btw, when you did d.) with the typo (divide by 2 instead of 3) you got 12 ?! you should have gotten (20+5^2)/2 = (20+25)/2 = 45/2 = 22.5 which is not 12.
@phi i did the wrong order oops
ok, just so you know how to do it correctly, because if don't understand order of operations, the rest of math assumes you know it, and you will get lost if you don't know them.
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