You draw 2 cards from a well-shuffled deck of 52 cards. After you draw the first card, you do not replace it in the deck. The probability of drawing the ace of spades on your first draw is 1/52. What is the probability of P(get queen of hearts on second draw | get ace of spades on first draw)?

Write fractions using the slash ( / ) key. Reduce fractions to their lowest terms.

Question

You draw 2 cards from a well-shuffled deck of 52 cards. After you draw the first card, you do not replace it in the deck. The probability of drawing the ace of spades on your first draw is 1/52. What is the probability of P(get queen of hearts on second draw | get ace of spades on first draw)?

Write fractions using the slash ( / ) key. Reduce fractions to their lowest terms.

anonymous · Answer

Let 

A = drawing the queen of hearts and
B = drawing the ace of spades 

our problem now becomes what is 

P(A | B).

Do you know a formula involving conditional probabilities?

anonymous · Answer

well, I was trying to use that formula to answer. however, the answer is simple "1/51"

anonymous · Answer

yup yup, since the events A and B are independent (i.e. drawing cards in either order yields the same probability), the answer is 1/51.  Good job :)