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Mathematics 18 Online
OpenStudy (anonymous):

pic posted

OpenStudy (anonymous):

OpenStudy (anonymous):

there's 9 that are less than 6 (not including the 2)

OpenStudy (anonymous):

@Psymon help?

OpenStudy (psymon):

The chart is more confusing than it needs to be. I'm drawing my own on some scratch is all :P

OpenStudy (anonymous):

but DO U know how to do it...

OpenStudy (anonymous):

sorry my limit is 4 minutes for this question

OpenStudy (psymon):

Yeah, I dont think I know itwhen it comes to the term and being thrown in. Too rusty with it all.

OpenStudy (psymon):

Without the and, its just 4/36, but I know thats not the answer.

OpenStudy (anonymous):

so u don't know?? ugh! :(

OpenStudy (psymon):

Im not confident if I know and Id rather not give an answer and say its correct.

OpenStudy (psymon):

Otherwise Id say 4/36 reduces to 1/9

OpenStudy (psymon):

Amount of occurence divided by possibilities. 4 occurences of a 2 showing once and being less than 6 divided by 36 overall outcomes means 4/36. Thats what I got, but Im not confident in it.

OpenStudy (anonymous):

its not 4/36 in the 1st place..

OpenStudy (psymon):

Well, itd reduce to 1/9. But like I said, Im not confident in my answer *shrugs*

OpenStudy (anonymous):

not including the 2 there are 9 numbers less than 6

OpenStudy (psymon):

Right. Which is why I said the and throws me off. Im no good with probability. Sorry no-one else came.

OpenStudy (anonymous):

@vinnv226

OpenStudy (anonymous):

even without the "and" its 9/36... :(

OpenStudy (anonymous):

There are 5 outcomes, out of 36, so 5/36

OpenStudy (anonymous):

what???

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (psymon):

It only wants one 2, though.

OpenStudy (anonymous):

It doesn't say that

OpenStudy (anonymous):

there is only one 2!

OpenStudy (psymon):

It just says one die shows a 2. I take that to mean just whatit says.

OpenStudy (anonymous):

If one die shows a 2, the other die could be anything. It does not say "exactly one" die shows a 2. Based on the current wording of the problem, it would be 5/36

OpenStudy (anonymous):

wouldn't it be 9/36 * 1/6 ???

OpenStudy (psymon):

No, because those are simply only the sums that are less than 6. It needs to satisfy the condition of having a 2 as well.

OpenStudy (anonymous):

oh cuz it says AND?

OpenStudy (psymon):

Yeah.

OpenStudy (anonymous):

so then... I don't get this

OpenStudy (anonymous):

You need to find the outcomes where one die has a 2, and the sum is less than 6. So eliminate all the sums that are 6 or over. Then, which of the remaining outcomes has a 2 in it? See my screenshot i uploaded, I marked the 5 outcomes.

OpenStudy (anonymous):

they don't have a 2 in it... :( ?

OpenStudy (anonymous):

oh wait I see it cuz to the left/right it can go above 6 but theyre all in the "2" section...

OpenStudy (anonymous):

oh ok.. keep going actually

OpenStudy (anonymous):

but it says "and ONE die shows a 2" ??

OpenStudy (anonymous):

Right, so at least one die needs to show a 2, so you eliminate all outcomes that don't have a 2 in them

OpenStudy (anonymous):

so why is it in both of the dice there is a 2? it says "one" right?

OpenStudy (anonymous):

ohh. ok.. so its 5/36?

OpenStudy (anonymous):

Right, so they're talking about one of the 2 dice. The other die is irrelevant

OpenStudy (anonymous):

but the answer is still 5/26..

OpenStudy (anonymous):

5/36 I mean?

OpenStudy (anonymous):

So what if there was a problem like this: You toss 3 coins. What is the probability that you get exactly 3 heads given that you get at least one head???

OpenStudy (anonymous):

@vinnv226

OpenStudy (anonymous):

I'm pretty sure I answered that exact problem earlier today

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