A set of data points has an equation of = -1.5 + 2.5x. What is the residual for the point (5,12)? A. 11 B. -1 C. 1 D. 12
difference between the actual \(y\) value and the predicted \(y\) value i.e. plug in \(5\) in to \(y=-1.5 + 2.5x\) for \(x\) and find what \(y\) you get
i get \(y=-1.5+2.5\times 5=11\)
i got 14
what did i do wrong?
but instead of \(11\) you have \(12\) which lies one unit above \(11\)
i don't know, i used a calculator
but we can do the arithmetic if you like
\[-1.5\times 2.5\times 5=-1.5+12.5=11\]
in any case since \(12\) is one unit higher, the "residual' is \(1\)
so i just plug in the y value in for x ?
oh you added!!
so the x value goes in the x spot right? and it supposed to equal the y value?
steps are 1) plug in \(5\) for \(x\) in the formula 2) compare the number you get with the \(y\) coordinate of \((5,12)\) i.e. compare it to \(12\)
got it ! thank you.
since \(12\) is one unit above the \(11\) you get from the formula, the "residual" is one
and for this one i would bet an even $10 that it is right yw
you were right :)
does the y mean anything special? in the equation
on the link ^^
you know i don't actually know squat about data analysis, i just google "residual" to get your last answer for this one, i would just replace \(x\) by \(15\) and see what you get i can't imagine it can be anything else
alright thank you
Join our real-time social learning platform and learn together with your friends!