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Find the zeros of the function by using the Quadratic Formula. f(x) = x2 + 3x - 7
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Please explain! I thought it would be a simple answer but my choices seem complex..So confused.
the quadratic formula is \(\large{x={-b\pm\sqrt{b^2-4ac}\over2a}}\) where \(f(x)=ax^2+bx+c\)
so for your equation \(f(x)=\color{red}{1}x^2\color{blue}{+3}x\color{green}{-7}\) the quadratic is to be solved as such:\[x={-\color{red}{3}\pm\sqrt{\color{red}{3}^2-4(\color{blue}{1})(\color{green}{-7})}\over2(\color{blue}{1})}\]now just solve through, and be mindful of the "\(\pm\)" sign, which means plus or minus, so you'll end up with two answers :)
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