Question

solve 2x^2 + x < 3

Answer 1

start with
\[2x^2+x-3<0\] then see if you can factor

Answer 2

not too hard to factor this one

Answer 3

@satellite73 sorry, when I get here I suffer with a crazy delay.. I found the roots but it doesnt work on the graph

Answer 4

not sue what you mean

Answer 5

factors as
\[(x-1)(2x+3)\] zeros are \(-\frac{3}{2}\) and \(1\)

Answer 6

since it is a parabola that opens up, it is negative between the zeros, and positive outside of them
you want negative, so the final answer is \(-\frac{3}{2}<x<1\) or \((-\frac{3}{2},1)\) in interval notation

Answer 7

I thought it was -3 and 2

Answer 8

hmmm no

Answer 9

2x^2+x-3 what happens then?