Question

(16/81) to the power -3/4 ?

Answer 1

Well observe:$$16=4^2=(2^2)^2=2^4\\81=9^2=(3^2)^2=3^4$$

Answer 2

the exponent has three parts
denominator, that means take the fourth root
numerator, that means cube it
a minus sign, that means take the reciprocal

Answer 3

That means: \[\sqrt[4]{(\frac{ 81 }{ 16 })^{3}}\]

Answer 4

ooh, thanks:D

Answer 5

the fourth root of \(16\) is \(2\) because \(2^4=16\)
when you cube \(\) you get \(2^3=8\)
repeat the process for \(81\) then flip the result

Answer 6

@ivancsc1996 fourth-root is probably a better idea to do first when computing

Answer 7

Yes you are right. @shanzayxox98 It's better to use:\[(\sqrt[4]{\frac{ 81 }{ 16 }})^{3}\]