Question

Maya plots three points in her notebook and joins two of the points using a straight line, as shown.

Maya makes the following statements about the points.

Statement 1: Point A, Point B, and Point C are contained on one plane.
Statement 2: One plane contains line AC and Point B.

Which chart best justifies Maya’s statements?

Answer 1

A:
Postulate: Through any three noncollinear points, there is exactly one plane.
Theorem: If a point lies outside a line, then exactly one plane contains both the line and the point.

B:
Postulate: A plane contains at least two collinear points and one noncollinear point.
Theorem: If a point lies outside a line, then the planes that contain both the line and the point coincide.

C:
Postulate: If a point lies outside a line, then exactly one plane contains both the line and the point.
Theorem: Through any three noncollinear points, there is exactly one plane.

D:
Postulate: If a point lies outside a line, then the planes that contain both the line and the point coincide.
Theorem: A plane contains at least two collinear points and one noncollinear point.

Answer 2

@hba @Luigi0210 You guys got any idea at all?